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JSON.parse() throws “unexpected token” error for valid JSON

Although your JSON string is valid JSON.parse is likely to throw error. This is because JSON.parse cannot parse some special characters that are \n, \t, \r and \f.

You need to escape these special characters for before passing JSON string to JSON.parse function.

Here is a function that takes a JSON string and escapes the special characters:

        function escapeSpecialChars(jsonString) {

            return jsonString.replace(/\n/g, "\\n")
                .replace(/\r/g, "\\r")
                .replace(/\t/g, "\\t")
                .replace(/\f/g, "\\f");

        }
Narayan Prusty
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Comments: 3
  1. Tyler Collier
    6 years ago

    Don’t forget about \", as mentioned on this stackoverflow answer.

    ReplyCancel
  2. Gajapathi
    6 years ago

    Thanks for this lovely post

    ReplyCancel
  3. Gajapathi
    6 years ago

    Very Helpful, after wasting my 2 hrs of time, i found this, and ended my serach for JSON.parse error

    ReplyCancel

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Narayan Prusty

I am a software engineer specialising in Blockchain, DevOps and Go/JavaScript. This is my personal blog where I write about things that I learn and feel interesting to share.

7 years ago 3 Comments Web Development
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